How to Fix the “Cannot read property of undefined” Error in JavaScript

4 ways to fix the “Cannot read property of undefined” error in JavaScript.

The error happening in Chrome.
The error happening in Chrome.

1. Add undefined check on variable

To fix the the error, check that the value is not undefined before accessing the property:

JavaScript
const auth = undefined; console.log(auth); // undefined // ❌ TypeError: Cannot read properties of undefined (reading 'user') console.log(auth.user.name); 

We can fix the error by adding an optional chaining operator (?.) on the variable before accessing a property. If the variable is undefined or null, the operator will return undefined immediately and prevent property access.

JavaScript
const auth = undefined; console.log(auth); // undefined // ✅ No error console.log(auth?.user?.name); // undefined 

The optional chaining operator also works when using bracket notation for property access:

JavaScript
const auth = undefined; console.log(auth); // undefined // ✅ No error console.log(auth?.['user']?.['name']); // undefined 

This means that we can use it on arrays:

JavaScript
const arr = undefined; console.log(arr?.[0]); // undefined // Array containing an object console.log(arr?.[2]?.prop); // undefined

Before the optional chaining was available, the only way we could avoid this error was to manually check for the truthiness of every containing object of the property in the nested hierarchy, for example:

JavaScript
const a = undefined; // Optional chaining if (a?.b?.c?.d?.e) { console.log(`e: ${e}`); } // No optional chaining if (a && a.b && a.b.c && a.b.c.d && a.b.c.d.e) { console.log(`e: ${e}`); }

2. Use replacement for undefined variable

In the first approach, we don’t access the property or method when the variable turns out to be undefined. In this solution, we provide a fallback value that we’ll access the property or method on.

Here, we use ?? to set the variable to a default string value if undefined, to avoid the “Cannot read property ‘replace’ of undefined” error.

JavaScript
const str = undefined; const result = (str ?? 'old str').replace('old', 'new'); console.log(result); // 'new str'

The null coalescing operator (??) returns the value to its left if it is not null or undefined. If it is, then ?? returns the value to its right.

JavaScript
console.log(5 ?? 10); // 5 console.log(undefined ?? 10); // 10

The logical OR (||) operator can also do this:

JavaScript
console.log(5 || 10); // 5 console.log(undefined || 10); // 10

3. Use fallback value instead of accessing property

Another way to fix this error is to avoid the property access altogether when the variable is undefined and use a default fallback value instead.

We can do this by combining the optional chaining operator (?.) and the nullish coalescing operator (??).

By using 0 as a fallback in this example, we prevent the “Cannot read property ‘length’ of undefined” error.

JavaScript
const arr = undefined; // Using "0" as a fallback value const arrLength = arr?.length ?? 0; console.log(arrLength); // 0 const str = undefined; // Using "0" as a fallback value const strLength = str?.length ?? 0; console.log(strLength); // 0

4. Find out why the variable is undefined

The solutions above are handy when we don’t know beforehand if the variable will be undefined or not. But there are situations where the “cannot read property of undefined” error is caused by a coding error that led to the variable being undefined.

Make sure variables are initialized

It could be that you forgot to initialize the variable:

JavaScript
let doubles; const nums = [1, 2, 3, 4, 5]; for (const num of nums) { let double = num * 2; // ❌ TypeError: cannot read properties of undefined (reading 'push') doubles.push(double); } console.log(doubles);

In this example, we call the push() method on the doubles variable without first initializing it, which causes the “Cannot read property ‘push’ of undefined” error.

JavaScript
let doubles; console.log(doubles); // undefined

Because an uninitialized variable has a default value of undefined in JavaScript, accessing a property/method causes the error to be thrown.

The obvious fix for the error, in this case, is to assign the variable to a defined value.

JavaScript
// ✅ "doubles" initialized before use let doubles = []; let nums = [1, 2, 3, 4, 5]; for (const num of nums) { let double = num * 2; // push() called - no error thrown doubles.push(double); } console.log(doubles); // [ 2, 4, 6, 8, 10 ]

Make sure called function returns value

If the property you’re accessing is from a function call result, the error may have occurred because you forgot to actually return a value in the function.

This mistake commonly causes the “Cannot read property ‘then’ of undefined” error in JavaScript:

JavaScript
function fetchData(apiUrl) { // 👇 `return` keyword missing fetch(apiUrl).then((response) => { return response.json(); }); } // ❌ Cannot read property 'then' of undefined fetchData('/api/data') .then((data) => console.log(data))

To fix the error in this case, we’ll simply return fetch()‘s Promise:

JavaScript
async function getUserData(userId) { if (userId) { const response = await fetch(`/api/users/${userId}`); return response.json(); } // 😕 No return if userId is absent } // ❌ Cannot read property 'then' of undefined if userId is absent getUserData().then(data => console.log(data));

Make sure type is correct

Another common mistake that causes this error is accessing an element from an array variable before accessing an Array property/method instead of accessing the property/method on the actual array variable.

JavaScript
const array = []; // ❌ TypeError: Cannot read properties of undefined (reading 'push') array[0].push('html'); array[0].push('css'); array[0].push('javascript'); console.log(array);

Accessing the 0 property with bracket indexing gives us the element at the index 0 of the array. The array has no element, so arr[0] evaluates to undefined and calling push() on it causes the error.

To fix this, we need to call the method on the array variable, not one of its elements.

JavaScript
const array = []; // ✅ Call push() on "array" variable, not "array[0]" array.push('html'); array.push('css'); array.push('javascript'); console.log(array); // [ 'html', 'css', 'javascript' ]


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